Additional examples are adjusted to the entries in an automated way - we cannot guarantee that they are correct.
This turns out to be because 10 is a composite number.
Twelve is also a highly composite number, the next one being 24.
In contrast, the decision problem "is N a composite number?"
One key is a large composite number, which the owner may distribute publicly.
It is particularly effective at splitting composite numbers with small factors.
In fact, only 449 superabundant and highly composite numbers are the same.
Nine is a composite number, its proper divisors being 1 and 3.
Usually is given as a prime, but composite numbers work as well.
However, no finite set of bases is sufficient for all composite numbers.
In general, if is a composite number, then does not satisfy the zero-product property.
It is neither a prime number nor a composite number.
The concept is somewhat analogous to that of highly composite numbers.
There are an infinite number of highly composite numbers.
One way to classify composite numbers is by counting the number of prime factors.
It is a composite number, with its divisors being 2, 5, 10, 23, 46, and 115.
To prove this fact, suppose that n is an arbitrary highly composite number.
Highly composite numbers higher than 6 are also abundant numbers.
There are also no known composite numbers above that bound that pass the test.
A trivial example would be any large composite number accumulates its prime factors.
This property is useful for finding highly composite numbers.
The initial or smallest twenty-one highly composite numbers are listed in the table at right.
Forty-eight is a double factorial of 6, a highly composite number.
However, it is the largest (and only) composite number n for which is false.
For example, the integer 14 is a composite number because it can be factored as 2 x 7.
It is a highly composite number, having more divisors than any smaller number.